(2x+1)(x^2-6x+2)=0

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Solution for (2x+1)(x^2-6x+2)=0 equation:


Simplifying
(2x + 1)(x2 + -6x + 2) = 0

Reorder the terms:
(1 + 2x)(x2 + -6x + 2) = 0

Reorder the terms:
(1 + 2x)(2 + -6x + x2) = 0

Multiply (1 + 2x) * (2 + -6x + x2)
(1(2 + -6x + x2) + 2x * (2 + -6x + x2)) = 0
((2 * 1 + -6x * 1 + x2 * 1) + 2x * (2 + -6x + x2)) = 0
((2 + -6x + 1x2) + 2x * (2 + -6x + x2)) = 0
(2 + -6x + 1x2 + (2 * 2x + -6x * 2x + x2 * 2x)) = 0
(2 + -6x + 1x2 + (4x + -12x2 + 2x3)) = 0

Reorder the terms:
(2 + -6x + 4x + 1x2 + -12x2 + 2x3) = 0

Combine like terms: -6x + 4x = -2x
(2 + -2x + 1x2 + -12x2 + 2x3) = 0

Combine like terms: 1x2 + -12x2 = -11x2
(2 + -2x + -11x2 + 2x3) = 0

Solving
2 + -2x + -11x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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